6x^2+x=98

Solution for 6x^2+x=98 equation:

6x^2+x=98

We move all terms to the left:

6x^2+x-(98)=0

a = 6; b = 1; c = -98;
Δ = b2-4ac
Δ = 12-4·6·(-98)
Δ = 2353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2353}}{2*6}=\frac{-1-\sqrt{2353}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2353}}{2*6}=\frac{-1+\sqrt{2353}}{12}
$